![]() ![]() ![]() What if Spider-Man's webs are stored in another dimension and his web shooters just grab them and pull them into this dimension? Wouldn't that explain how he can shoot so many webs? Yes.If he did have webs as part of his super hero powers, the webs would probably come out of his butt and not his wrist. I suspect they did that because they didn't want to spend the time to show how Peter Parker developed the webs. That was from the previous Spider-Man movies. I thought Spider-Man's webs came out of his wrist and were just part of his super hero powers.Why are you wasting your time on stupid posts like this? Don't you have more important things to do as a physicist? Maybe you should be working on fusion or other clean power sources? You are probably correct, but I just can't help myself.However, it would be difficult to estimate the compression inside the shooter. Couldn't it be packed in even tighter when inside? Yes, this is possible. You assumed that the density of Spider-Man's webs once it comes out of the shooter is the same as the density inside the shooter. Toby McGuire is the real Spider-Man, not this guy that looks like Anakin Skywalker. In that case, he would have a range of 163 meters.Īnd now for some preemptive comments and answers: Oh, but maybe he can ramp up the launch speed up to 40 m/s for those special occasions. Putting in an angle of 45°, Spider-Man gets a range of 58.8 meters. The mass of this section of web can be found from the density of 0.55 g/cm 3. It’s not too difficult, but if you want the details check out this previous post.įor this simulation, I am going to assume carbon nanotube webs with a radius of 1 mm and a length of 2 meters in a cylindrical shape. In cases like this, the only practical method for solving for the motion is to use a computer to create a numerical model. This means that there is a non-constant acceleration on this rising web. With a slower web there is also less air resistance. This means that I will just have to guess at a value for C. If a web is like a cylinder, a longer cylinder (as the web shoots out) has a different drag coefficient than a shorter web. The problem is with the value of C which is a coefficient that depends on the shape of the object. Here ρ is the density of air at about 1.2 kg/m 3 and A is the cross sectional area of the web. I could use the typical model for air resistance that say the force from air is proportional to the square of the speed: I’ll admit that calculating the air resistance in this case can be quite tricky. That doesn’t seem too bad, does it? But wait. Sure, you could have just used one of the kinematic equations but what fun would that be? Using a the value for the change in height of 30 meters, the web launch speed would be 24.2 m/s (54 mph). Now I can use the average velocity and this time interval to get an expression for the change in vertical position.Īnd there is your expression for the launch speed of the web. Here is a look at my device looking down the arm. Now I can calculate the thickness of this container. In my web container design, I will let the cartridge go back 10 cm along my arm. What would this look like if it fit around a wrist? If I use my own wrist for a basis, then I find that it has a circumference of 16.5 cm. That gives a total volume (per hand) of 0.00314 m 3. In that case, we can find the web volume estimation by a factor of 50. If I were Spider-Man, that’s what I would want. Well, then how big of a container would he need to have a reasonable number of shots? Let’s say he wants 50 uses of the web for each hand. That’s a long pencil and remember, that’s for just one of his typical web shots. If all of this webbing was put into a pencil, the pencil would be 3.2 m long. How about a comparison to the volume of a standard pencil with a radius of 0.25 cm. That might be a little difficult to visualize in terms of the size. ![]() This would put the total web volume for one use at 6.28 x 10 -5 m 3. Well, the steel cable could work but it would have to be much thicker with a radius of 2.5 mm. Carbon nanotube rope: 1.98 x 10 5 Newtonsīased on these calculations, it looks like carbon nanotube rope is the only thing that would work.If I replaced the web with real materials of the same size, this would be their maximum tension (based on the values from Wikipedia). Let me approximate the web shot from Spider-Man as a cylindrical shape with a radius of 1 mm. Here comes the first wild estimate (ok, not the first). In order to get a maximum tension, you need to know the cross sectional area of the wire since obviously thicker wires are stronger. This is the maximum tension per cross sectional area that the material can withstand before breaking and is measured in units of MPa (mega Pascals - or 10 6 Newtons/m 2. The strength of a material can be describe by the ultimate tensile strength. Let’s use this value to make a comparison to other web-like options.
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